-32/20^2x^2+x+3=0

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Solution for -32/20^2x^2+x+3=0 equation: 


x in (-oo:+oo)

(-32/(20^2))*x^2+x+3 = 0

x-2/25*x^2+3 = 0

DELTA = 1^2-(-2/25*3*4)

DELTA = 49/25

DELTA > 0

x = ((49/25)^(1/2)-1)/(-2/25*2) or x = (-(49/25)^(1/2)-1)/(-2/25*2)

x = -5/2 or x = 15

x in { -5/2, 15 }

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